**** Post for FREE via your newsreader at post.usenet.com ****
Misti Norton said:
TYou were doing well, until this last statement.
You "lock a wheel" when the retardation force acting to reduce rotation is
greater than the static friction interaction between the tyre and the road.
In other words, it doesn't matter if the braking force is concentrated
entirely at the brakes, or in combonation with engine braking, the same
amount of "total braking effort" at that wheel will casuse the wheel to
lock. Doesn't matter where in the transmission/brakeing system the braking
force is, as it all comes together at the tyre/road interface, and THAT is
where it counts. how can the tyre tell if the braking force comes from the
rotor, or the engine? Bit of common sense there please.
Granted the road nor the tire (tyre) care when dynamic pull overcomes static
friction, the case is still there of how the ABS manages this breaking
situation. That was my arguement in the first place. However I will add that
if engine braking results in a slide requiring ABS-like properties, KYAGB
(Kiss You Ass Good Bye) since you are going where ever inertia is going to
take you.
To me the difference between clutch engaged and not engaged is this, when
breaking there is a slight input from the engine to contribute in the
"directed" direction. Without the clutch engaged, the engine means weight
only and you are using ABS on a Red Rider Wagon. The difference being that
with the clutch engaged the engine is giving it's input, you have a
direction to tell to the ABS system (ie - that of the direction of the
tires). While engaged, the system will think it's at a stop light while you
might be spinning like a top.
-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=
*** Usenet.com - The #1 Usenet Newsgroup Service on The Planet! ***
http://www.usenet.com
Unlimited Download - 19 Seperate Servers - 90,000 groups - Uncensored
-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=